2x^2-20x+82=0

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Solution for 2x^2-20x+82=0 equation:


Simplifying
2x2 + -20x + 82 = 0

Reorder the terms:
82 + -20x + 2x2 = 0

Solving
82 + -20x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(41 + -10x + x2) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(41 + -10x + x2)' equal to zero and attempt to solve: Simplifying 41 + -10x + x2 = 0 Solving 41 + -10x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '-41' to each side of the equation. 41 + -10x + -41 + x2 = 0 + -41 Reorder the terms: 41 + -41 + -10x + x2 = 0 + -41 Combine like terms: 41 + -41 = 0 0 + -10x + x2 = 0 + -41 -10x + x2 = 0 + -41 Combine like terms: 0 + -41 = -41 -10x + x2 = -41 The x term is -10x. Take half its coefficient (-5). Square it (25) and add it to both sides. Add '25' to each side of the equation. -10x + 25 + x2 = -41 + 25 Reorder the terms: 25 + -10x + x2 = -41 + 25 Combine like terms: -41 + 25 = -16 25 + -10x + x2 = -16 Factor a perfect square on the left side: (x + -5)(x + -5) = -16 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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